What is the range of (3+x)/(x-2) ?

The range of (3+x)/(x-2) is f(x) 1

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range of (3+x)/(x-2)

range

\frac{3 + x}{x - 2}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{3 + x}{x - 2}

Inverse of

\frac{3 + x}{x - 2} : \frac{3 + 2 x}{x - 1}

\frac{3 + 2 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{3 + 2 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

9 - x

f (x) = \frac{1}{17 - t}

x + 3 - 1

f (x) = - \frac{7}{2 x ^{\frac{3}{2}}}

(2.8) (1.3)

What is the range of (3+x)/(x-2) ?
The range of (3+x)/(x-2) is f(x)<1\lor f(x)>1