What is the f(y)=((y-1))/(ln(y)) ?

The f(y)=((y-1))/(ln(y)) is Domain: 0 1 Intercepts: None Asymptotes: None

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f(y)=((y-1))/(ln(y))

f (y) = \frac{( y - 1 )}{ln ( y )}

Domain : 0 < y < 1 or y > 1

Intercepts : None

Asymptotes : None

Interval Notation

Domain : (0, 1) \cup (1, \infty)

Solution steps

Domain of

\frac{y - 1}{ln ( y )} : 0 < y < 1 or y > 1

Axis interception points of

\frac{y - 1}{ln ( y )} :

None

Asymptotes of

\frac{y - 1}{ln ( y )} :

None

f (x) = 3 x^{2} + 5 x + 8

y = tan^{2} (∣ x ∣)

f (x) = 2 x^{3} + 3 x - 2

f (x) = 7 sin (x) - 4 x^{2} cos (x)

f (x) = \frac{19}{( 2 x + 5 )}

What is the f(y)=((y-1))/(ln(y)) ?
The f(y)=((y-1))/(ln(y)) is Domain: 0<y<1\lor y>1<br/>Intercepts: None<br/>Asymptotes: None