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Popular >

f(t)=t^2-20t+200

Solution

f (t) = t^{2} - 20 t + 200

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq 100

Y Intercepts : (0, 200)

Vertex : Minimum (10, 100)

Inverse : 10 + t - 100, 10 - t - 100

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [100, \infty)

Solution steps

Domain of

t^{2} - 20 t + 200 : - \infty < t < \infty

Range of

t^{2} - 20 t + 200 : f (t) \geq 100

Axis interception points of

t^{2} - 20 t + 200 :

Y Intercepts

: (0, 200)

Vertex of

t^{2} - 20 t + 200 :

Minimum

(10, 100)

Inverse of

t^{2} - 20 t + 200 : 10 + t - 100, 10 - t - 100

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Frequently Asked Questions (FAQ)

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