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Popular >

y=(1+2x)^2(1.9)

Solution

y = (1 + 2 x)^{2} (1.9)

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 0

X Intercepts : (- \frac{1}{2}, 0), Y Intercepts : (0, 1.9)

Vertex : Minimum (- \frac{1}{2}, 0)

Inverse : \frac{\frac{10 x}{19} - 1}{2}, \frac{- \frac{10 x}{19} - 1}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [0, \infty)

Solution steps

Domain of

(1 + 2 x)^{2} 1.9 : - \infty < x < \infty

Range of

(1 + 2 x)^{2} 1.9 : f (x) \geq 0

Axis interception points of

(1 + 2 x)^{2} 1.9 :

X Intercepts

: (- \frac{1}{2}, 0),

Y Intercepts

: (0, 1.9)

Vertex of

(1 + 2 x)^{2} 1.9 :

Minimum

(- \frac{1}{2}, 0)

Inverse of

(1 + 2 x)^{2} 1.9 : \frac{\frac{10 x}{19} - 1}{2}, \frac{- \frac{10 x}{19} - 1}{2}

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Frequently Asked Questions (FAQ)

What is the y=(1+2x)^2(1.9) ?
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