What is p(x)=3,x^4+5x^3+9x^2-6=-1 ?

The solution to p(x)=3,x^4+5x^3+9x^2-6=-1 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p(x)=3,x^4+5x^3+9x^2-6=-1

p (x) = 3, x^{4} + 5 x^{3} + 9 x^{2} - 6 = - 1

(x = - 1, x = 0.63109 \dots, p = 3 p = 3)

Solution steps

[p = 3 x^{4} + 5 x^{3} + 9 x^{2} - 6 = - 1]

Solve

x^{4} + 5 x^{3} + 9 x^{2} - 6 = - 1 : x = - 1, x \approx 0.63109 \dots

For

p = 3

, subsitute

x

with

- 1 : p = 3

For

p = 3

, subsitute

x

with

0.63109 \dots : p = 3

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

p = 3, x^{4} + 5 x^{3} + 9 x^{2} - 6 = - 1

are

(x = - 1, x = 0.63109 \dots, p = 3 p = 3)

f (x) = x sin (x^{2}) + 1

f (r) = r^{3} - 8 r^{2} + 21 r + 18

y = \frac{x ^{2} + 2 x ^{3} - 1}{4 x ^{4}}

f (x) = - x^{4} + 3 x^{2} + 2

f (x) = x^{4} \cdot (4 - 6 x^{2} - 3 x^{2})

What is p(x)=3,x^4+5x^3+9x^2-6=-1 ?
The solution to p(x)=3,x^4+5x^3+9x^2-6=-1 is