What is the inverse of f(x)=(x-1)^2+5 ?

The inverse of f(x)=(x-1)^2+5 is sqrt(x-5)+1,-sqrt(x-5)+1

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inverse of f(x)=(x-1)^2+5

inverse

f (x) = (x - 1)^{2} + 5

x - 5 + 1, - x - 5 + 1

Solution steps

y = (x - 1)^{2} + 5

Replace

x

with

y

x = (y - 1)^{2} + 5

Solve for

y, x = (y - 1)^{2} + 5

x - 5 + 1, - x - 5 + 1

y = x^{2}

f (x) = - 2 x^{6} + 15 x^{5}

\frac{x - 3}{4 + 5 x}

m = - 2, (2, - 4)

f (x) = 6 x^{4} + 16 x^{3}

What is the inverse of f(x)=(x-1)^2+5 ?
The inverse of f(x)=(x-1)^2+5 is sqrt(x-5)+1,-sqrt(x-5)+1