What is the f(t)=sqrt(t^3)-sqrt((t^9)/4)+e ?

The f(t)=sqrt(t^3)-sqrt((t^9)/4)+e is

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f(t)=sqrt(t^3)-sqrt((t^9)/4)+e

f (t) = t^{3} - \frac{t ^{9}}{4} + e

Domain : t \geq 0

Asymptotes : None

Interval Notation

Domain : [0, \infty)

Solution steps

Domain of

t^{3} - \frac{t ^{9}}{4} + e : t \geq 0

Axis interception points of

t^{3} - \frac{t ^{9}}{4} + e :

X Intercepts

Y Intercepts

: (0, e)

Asymptotes of

t^{3} - \frac{t ^{9}}{4} + e :

None

Extreme Points of

t^{3} - \frac{t ^{9}}{4} + e :

Minimum

(0, e),

Maximum

f (x) = x^{2} - 56 x + 48

f (x) = \frac{1}{( x )}

f (x) = \frac{( 1 + cos ( x ) )}{( 1 - cos ( x ) )}

y = 0.5 x^{2} - 2 x - 7

y = 2 x^{3} + 3 x^{3} - 4 x - 1

What is the f(t)=sqrt(t^3)-sqrt((t^9)/4)+e ?
The f(t)=sqrt(t^3)-sqrt((t^9)/4)+e is