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Popular >

inverse of g(t)= 1/t+1

Solution

inverse

g (t) = \frac{1}{t} + 1

Solution

\frac{1}{t - 1}

Solution steps

y = \frac{1}{t} + 1

Replace

t

with

y

t = \frac{1}{y} + 1

Solve for

y, t = \frac{1}{y} + 1

\frac{1}{t - 1}

Popular Examples

critical x^3+6x critical points

x^{3} + 6 x

line m=-1/2 ,(-2,4)line

m = - \frac{1}{2}, (- 2, 4)

line 2x-5y=8 line

2 x - 5 y = 8

domain of-1 domain

- 1

critical f(x)= 1/2 x^2+8x+7 critical points

f (x) = \frac{1}{2} x^{2} + 8 x + 7

Frequently Asked Questions (FAQ)

What is the inverse of g(t)= 1/t+1 ?
The inverse of g(t)= 1/t+1 is 1/(t-1)