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Popular >

p(x)=x^2-1,-1,x=1

Solution

p (x) = x^{2} - 1, - 1, x = 1

Solution

Domain : x = 1

Range : f (x) = 0

X Intercepts : (1, 0)

Vertex : Minimum (0, - 1)

Inverse : x + 1, - x + 1

+1

Interval Notation

Domain : x = 1

Range : f (x) = 0

Solution steps

Domain of

x^{2} - 1, x = 1 : x = 1

Range of

x^{2} - 1, x = 1 : f (x) = 0

Axis interception points of

x^{2} - 1, x = 1 :

X Intercepts

: (1, 0)

Vertex of

x^{2} - 1, x = 1 :

Minimum

(0, - 1)

Inverse of

x^{2} - 1, x = 1 : x + 1, - x + 1

Popular Examples

f(x)=x^3-x^2+2x+3

f (x) = x^{3} - x^{2} + 2 x + 3

f(x)=-8x^3+56x^2+x-7

f (x) = - 8 x^{3} + 56 x^{2} + x - 7

y = (2 x + 3) (3 x - 5)

f(x)=x^4+2x^3+x^2+1

f (x) = x^{4} + 2 x^{3} + x^{2} + 1

f(x)=x^3-23x^2+142x+20

f (x) = x^{3} - 23 x^{2} + 142 x + 20

Frequently Asked Questions (FAQ)

What is the p(x)=x^2-1,-1,x=1 ?
The p(x)=x^2-1,-1,x=1 is