What is the y=((x^2+3))/(((3sqrt(x)-4)^2)) ?

The y=((x^2+3))/(((3sqrt(x)-4)^2)) is

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y=((x^2+3))/(((3sqrt(x)-4)^2))

y = \frac{( x ^{2} + 3 )}{( ( 3 x - 4 ) ^{2} )}

Domain : 0 \leq x < \frac{16}{9} or x > \frac{16}{9}

Y Intercepts : (0, \frac{3}{16})

Asymptotes : Vertical x = \frac{16}{9}

Extreme Points : Minimum (0, \frac{3}{16}), Minimum (7.85627 \dots, 3.32982 \dots)

Interval Notation

Domain : [0, \frac{16}{9}) \cup (\frac{16}{9}, \infty)

Solution steps

Domain of

\frac{x ^{2} + 3}{( 3 x - 4 ) ^{2}} : 0 \leq x < \frac{16}{9} or x > \frac{16}{9}

Axis interception points of

\frac{x ^{2} + 3}{( 3 x - 4 ) ^{2}} :

Y Intercepts

: (0, \frac{3}{16})

Asymptotes of

\frac{x ^{2} + 3}{( 3 x - 4 ) ^{2}} :

Vertical

: x = \frac{16}{9}

Extreme Points of

\frac{x ^{2} + 3}{( 3 x - 4 ) ^{2}} :

Minimum

(0, \frac{3}{16}),

Minimum

(7.85627 \dots, 3.32982 \dots)

f (x) = - 4 (x + 3)^{2} + 5

f ((x)) = \frac{( 1 )}{( 1 - 3 x )}

f (x) = \frac{( x ^{2} + 2 )}{( x + 5 )}

y = 2 x^{2} + 4 x - 8

y = 2^{1 - x}, - 2 \leq x < 3

What is the y=((x^2+3))/(((3sqrt(x)-4)^2)) ?
The y=((x^2+3))/(((3sqrt(x)-4)^2)) is