What is the p(x)=-4x^2+24x-32 ?

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p(x)=-4x^2+24x-32

p (x) = - 4 x^{2} + 24 x - 32

Domain : - \infty < x < \infty

Range : f (x) \leq 4

X Intercepts : (2, 0), (4, 0), Y Intercepts : (0, - 32)

Vertex : Maximum (3, 4)

Inverse : - \frac{- 6 + - x + 4}{2}, \frac{- x + 4 + 6}{2}

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 4]

Solution steps

Domain of

- 4 x^{2} + 24 x - 32 : - \infty < x < \infty

Range of

- 4 x^{2} + 24 x - 32 : f (x) \leq 4

Axis interception points of

- 4 x^{2} + 24 x - 32 :

X Intercepts

: (2, 0), (4, 0),

Y Intercepts

: (0, - 32)

Vertex of

- 4 x^{2} + 24 x - 32 :

Maximum

(3, 4)

Inverse of

- 4 x^{2} + 24 x - 32 : - \frac{- 6 + - x + 4}{2}, \frac{- x + 4 + 6}{2}

f (x) = sin (x^{2} + 5 x + 7)

\frac{( \frac{2}{3} ) x + 4}{3}

f (x) = x^{3} - 3 x^{2} + 5 x - 7

p (1) = x^{3} - 23 x^{2} + 142 x - 120

f (x) = sin (\frac{1}{( x - 1 )})