en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

amplitude of 2/5 sin(x)

Solution

amplitude

\frac{2}{5} sin (x)

Solution

0.4

Solution steps

f (x) = \frac{2}{5} sin (x), A = \frac{2}{5}

Therefore, the amplitude |A| is

0.4

0.4

Popular Examples

intercepts of f(x)=5x-4y=30 intercepts

f (x) = 5 x - 4 y = 30

critical f(x)=x^3-6x^2-15x+40 critical points

f (x) = x^{3} - 6 x^{2} - 15 x + 40

domain of f(x)=((x^2-1))/(x^2+1)domain

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + 1}

intercepts of f(x)=x^3-4x^2 intercepts

f (x) = x^{3} - 4 x^{2}

range of f(x)=(x^2-4)/(x^2)range

f (x) = \frac{x ^{2} - 4}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the amplitude of 2/5 sin(x) ?
The amplitude of 2/5 sin(x) is 0.4