What is the inverse of f(x)=sqrt(2x-1)+3 ?

The inverse of f(x)=sqrt(2x-1)+3 is (x^2-6x+10)/2

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inverse of f(x)=sqrt(2x-1)+3

inverse

f (x) = 2 x - 1 + 3

\frac{x ^{2} - 6 x + 10}{2}

Solution steps

y = 2 x - 1 + 3

Replace

x

with

y

x = 2 y - 1 + 3

Solve for

y, x = 2 y - 1 + 3

\frac{x ^{2} - 6 x + 10}{2}

3^{2 x - 1}

- 5 sin (29 (x - 3)) - 8

f (x) = \frac{3 x - 4}{x + 2}

x^{\frac{2}{3}} - x^{\frac{1}{3}}

y = x^{3} - 12 x + 6

What is the inverse of f(x)=sqrt(2x-1)+3 ?
The inverse of f(x)=sqrt(2x-1)+3 is (x^2-6x+10)/2