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Popular >

h(t)=10(t^3+4t^2+t-6)

Solution

h (t) = 10 (t^{3} + 4 t^{2} + t - 6)

Solution

Domain : - \infty < t < \infty

Range : - \infty < f (t) < \infty

X Intercepts : (1, 0), (- 2, 0), (- 3, 0), Y Intercepts : (0, - 60)

Asymptotes : None

Extreme Points : Maximum (- \frac{4 + 13}{3}, 10 (\frac{92 + 26 13}{27} - 6)), Minimum (\frac{- 4 + 13}{3}, 10 (\frac{92 - 26 13}{27} - 6))

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

10 (t^{3} + 4 t^{2} + t - 6) : - \infty < t < \infty

Range of

10 (t^{3} + 4 t^{2} + t - 6) : - \infty < f (t) < \infty

Axis interception points of

10 (t^{3} + 4 t^{2} + t - 6) :

X Intercepts

: (1, 0), (- 2, 0), (- 3, 0),

Y Intercepts

: (0, - 60)

Asymptotes of

10 (t^{3} + 4 t^{2} + t - 6) :

None

Extreme Points of

10 (t^{3} + 4 t^{2} + t - 6) :

Maximum

(- \frac{4 + 13}{3}, 10 (\frac{92 + 26 13}{27} - 6)),

Minimum

(\frac{- 4 + 13}{3}, 10 (\frac{92 - 26 13}{27} - 6))

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Frequently Asked Questions (FAQ)

What is the h(t)=10(t^3+4t^2+t-6) ?
The h(t)=10(t^3+4t^2+t-6) is