What is the f(x)=sqrt((x+2)/(x^2-9)) ?

The f(x)=sqrt((x+2)/(x^2-9)) is

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f(x)=sqrt((x+2)/(x^2-9))

f (x) = \frac{x + 2}{x ^{2} - 9}

Domain : - 3 < x \leq - 2 or x > 3

Range : f (x) \geq 0

X Intercepts : (- 2, 0)

Asymptotes : Vertical x = - 3, x = 3, Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- 3, - 2] \cup (3, \infty)

Range : [0, \infty)

Solution steps

Domain of

\frac{x + 2}{x ^{2} - 9} : - 3 < x \leq - 2 or x > 3

Range of

\frac{x + 2}{x ^{2} - 9} : f (x) \geq 0

Axis interception points of

\frac{x + 2}{x ^{2} - 9} :

X Intercepts

: (- 2, 0)

Asymptotes of

\frac{x + 2}{x ^{2} - 9} :

Vertical

: x = - 3, x = 3,

Horizontal

: y = 0

Extreme Points of

\frac{x + 2}{x ^{2} - 9} :

None

f (x) = \frac{1}{3 x ^{3} + 2 x ^{2} + 3 x}

f (x) = \frac{1}{3} x^{3} + \frac{3}{2} x^{2} - 4 x

f (x) = \frac{- 3 x ^{2} - 5 x + 2}{7}

f (x) = lo g_{10} (80 - 0.5 x)

f (x) = (3 x - 2 x^{2})^{3}