What is the y= 1/((e^x+1)^2) ?

The y= 1/((e^x+1)^2) is Parity: Neither even nor odd Inverse: ln(sqrt(1/x)-1),ln(-sqrt(1/x)-1)

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y= 1/((e^x+1)^2)

y = \frac{1}{( e ^{x} + 1 ) ^{2}}

Parity : Neither even nor odd

Inverse : ln (\frac{1}{x} - 1), ln (- \frac{1}{x} - 1)

Solution steps

Parity of

\frac{1}{( e ^{x} + 1 ) ^{2}} :

Neither even nor odd

Inverse of

\frac{1}{( e ^{x} + 1 ) ^{2}} : ln (\frac{1}{x} - 1), ln (- \frac{1}{x} - 1)

f (x) = \frac{2 x - 3}{3 x - 1}

y = 4 x^{2} - 24 x + 1

f (x) = 0.25 x^{2} - 30 x + 4000

f (x) = \frac{2 x}{x ^{2} - 1}

f (x) = - 2 x^{2} + 4 x + 8

What is the y= 1/((e^x+1)^2) ?
The y= 1/((e^x+1)^2) is Parity: Neither even nor odd<br/>Inverse: ln(sqrt(1/x)-1),ln(-sqrt(1/x)-1)