What is the f(x)=log_{2}(x^2-6x+8) ?

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f(x)=log_{2}(x^2-6x+8)

f (x) = lo g_{2} (x^{2} - 6 x + 8)

Domain : x < 2 or x > 4

Range : - \infty < f (x) < \infty

X Intercepts : (3 + 2, 0), (3 - 2, 0), Y Intercepts : (0, 3)

Asymptotes : Vertical x = 2, x = 4

Extreme Points : None

Interval Notation

Domain : (- \infty, 2) \cup (4, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

lo g_{2} (x^{2} - 6 x + 8) : x < 2 or x > 4

Range of

lo g_{2} (x^{2} - 6 x + 8) : - \infty < f (x) < \infty

Axis interception points of

lo g_{2} (x^{2} - 6 x + 8) :

X Intercepts

: (3 + 2, 0), (3 - 2, 0),

Y Intercepts

: (0, 3)

Asymptotes of

lo g_{2} (x^{2} - 6 x + 8) :

Vertical

: x = 2, x = 4

Extreme Points of

lo g_{2} (x^{2} - 6 x + 8) :

None

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p (x) = x^{3} - 7 x^{2} + x - 7

y = e^{3 x} sin^{4} (x)

f (x) = \frac{cos ( 2 θ ) + sin ^{2} ( θ )}{2 cos ( θ )}

f (x) = \frac{25 x + 50000}{x}