What is the axis y=48x-6x^2 ?

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axis y=48x-6x^2

axis

y = 48 x - 6 x^{2}

x = 4

Solution steps

y = 48 x - 6 x^{2}

Rewrite

y = 48 x - 6 x^{2}

in the standard form

4 (- \frac{1}{24}) (y - 96) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 96), p = - \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = 3 x^{2} + 6 x - 45

x = 14 (y - 4) (y + 10)

y = x^{2} - 2 x - 18

y = \frac{( 4 x + 5 ) ( 2 x + 3 )}{2}

y = x \cdot (x + 1)