What is the axis y=x^2-4x-32 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=x^2-4x-32

axis

y = x^{2} - 4 x - 32

x = 2

Solution steps

y = x^{2} - 4 x - 32

Rewrite

y = x^{2} - 4 x - 32

in the standard form

4 \cdot \frac{1}{4} (y - (- 36)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 36), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

(x + 2)^{2} = - 8 (y + 3)

y = \frac{1 + x ^{2} - 8 x}{5}

y^{2} + 6 x - 4 y - 11 = 0

(x + 3)^{2} = 2 (y - 4)

+ 3 y^{2} = 24 x