What is the axis (x+5)^2=-20(y-2) ?

The axis (x+5)^2=-20(y-2) is x=-5

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axis (x+5)^2=-20(y-2)

axis

(x + 5)^{2} = - 20 (y - 2)

x = - 5

Solution steps

(x + 5)^{2} = - 20 (y - 2)

Rewrite

(x + 5)^{2} = - 20 (y - 2)

in the standard form:

4 (- 5) (y - 2) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 2), p = - 5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 5

y = (x + 1)^{2} + 5

y = (- x + 1)^{2} + 2

y = - 0.5 x^{2} - 3

y = 3 x^{2} + 5 x - 4

y = 9 x^{2} - 5 x