What is the axis y=-x^2+64x-292 ?

The axis y=-x^2+64x-292 is x=32

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axis y=-x^2+64x-292

axis

y = - x^{2} + 64 x - 292

x = 32

Solution steps

y = - x^{2} + 64 x - 292

Rewrite

y = - x^{2} + 64 x - 292

in the standard form

4 (- \frac{1}{4}) (y - 732) = (x - 32)^{2}

Therefore parabola properties are:

(h, k) = (32, 732), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 32

y = - 45 x^{2} - 27 x + 2

y = - \frac{1}{2} (x - 3)^{2} - 8

y = x^{2} + 6 x + 9

y = 2 x^{2} - 5 x - 6

y = x^{2} - x - 2