What is the axis x=3y^2 ?

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axis x=3y^2

axis

x = 3 y^{2}

y = 0

Solution steps

x = 3 y^{2}

Rewrite

x = 3 y^{2}

in the standard form:

4 \cdot \frac{1}{12} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{12}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

4 y = - x^{2} - 12 x - 48

y = - 4 (x + 10)^{2} + 6

(x + 1)^{2} = - 3 (y - 6)

y = 10 x^{2} + 1 - 6 x

y = - 8 x^{2} + 4 x