What is the axis (x+5)^2=-2(y-2) ?

The axis (x+5)^2=-2(y-2) is x=-5

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axis (x+5)^2=-2(y-2)

axis

(x + 5)^{2} = - 2 (y - 2)

x = - 5

Solution steps

(x + 5)^{2} = - 2 (y - 2)

Rewrite

(x + 5)^{2} = - 2 (y - 2)

in the standard form:

4 (- \frac{1}{2}) (y - 2) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 2), p = - \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 5

x^{2} = - 36 y

y = + x^{2} - 12 x + 35

y = - 3 x^{2} - 6 x + 8

y = 2 (x - 2)^{2} + 9

y = x^{2} (0.1)