What is the axis y=(x-2+sqrt(5))(x-2-sqrt(5)) ?

The axis y=(x-2+sqrt(5))(x-2-sqrt(5)) is x=2

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axis y=(x-2+sqrt(5))(x-2-sqrt(5))

axis

y = (x - 2 + 5) (x - 2 - 5)

x = 2

Solution steps

y = (x - 2 + 5) (x - 2 - 5)

Rewrite

y = (x - 2 + 5) (x - 2 - 5)

in the standard form

4 \cdot \frac{1}{4} (y - (- 5)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 5), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

x^{2} + 2 x + 3 y + 22 = 0

y = - \frac{1}{4} x^{2} + x + 3

y = - \frac{1}{4} x^{2} + x + 6

+ y = x^{2} - 6 x + 8

y = (x)^{4} + 6 (x)^{2} - 1

What is the axis y=(x-2+sqrt(5))(x-2-sqrt(5)) ?
The axis y=(x-2+sqrt(5))(x-2-sqrt(5)) is x=2