What is the axis y=-x^2-3x-1 ?

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axis y=-x^2-3x-1

axis

y = - x^{2} - 3 x - 1

x = - \frac{3}{2}

Solution steps

y = - x^{2} - 3 x - 1

Rewrite

y = - x^{2} - 3 x - 1

in the standard form

4 (- \frac{1}{4}) (y - \frac{5}{4}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{5}{4}), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{2}

33 x^{2} - 3 {x - 2 x [x - 7 (x - 2) - 3] + 2} - 60 x

y = - x^{2} + 4 x + 3

y = - 6 x^{2} + 4 x + 9

y = \frac{5 x ^{3} + 21 x ^{2} + 17 x - 3}{x + 3}

y = 2000 x - 5 x^{2}