What is the axis y=-9x^2-7 ?

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axis y=-9x^2-7

axis

y = - 9 x^{2} - 7

x = 0

Solution steps

y = - 9 x^{2} - 7

Rewrite

y = - 9 x^{2} - 7

in the standard form:

4 (- \frac{1}{36}) (y - (- 7)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 7), p = - \frac{1}{36}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 3 x^{2} - 35 x

y = (x - 1)^{2} - 2

(y - 3)^{2} = - 20 (x + 2)

y = - x^{2} + 18 x - 82

(y + 4)^{2} = 4 (x + 1)