What is the axis y=3x^2-10x+5 ?

The axis y=3x^2-10x+5 is x= 5/3

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axis y=3x^2-10x+5

axis

y = 3 x^{2} - 10 x + 5

x = \frac{5}{3}

Solution steps

y = 3 x^{2} - 10 x + 5

Rewrite

y = 3 x^{2} - 10 x + 5

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{10}{3})) = (x - \frac{5}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{3}, - \frac{10}{3}), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{3}

y = x^{2} - 8

y = \frac{1}{17} (x + 5)^{2}

y = x^{2} + 100

x^{2} - 8 x + 14

f (x) = x^{2} - 18 x + 80