What is the axis y=log_{5}(2)x^2 ?

The axis y=log_{5}(2)x^2 is x=0

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axis y=log_{5}(2)x^2

axis

y = lo g_{5} (2) x^{2}

x = 0

Solution steps

y = lo g_{5} (2) x^{2}

Rewrite

y = lo g_{5} (2) x^{2}

in the standard form:

4 \cdot \frac{1}{4 lo g _{5} ( 2 )} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4 lo g _{5} ( 2 )}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 25 x^{2} - 100

y = \frac{x ^{2} + x}{2}

y = 3 x^{2} - 8 x - 3

x = (3 y - 4) (4 y - 3) - 2 y

y = - 2 x^{2} - 16 x - 25