What is 9x^2+9y^2+42x+84y+65=0 ?

The solution to 9x^2+9y^2+42x+84y+65=0 is Circle with (a,b)=(-7/3 ,-14/3),r=2sqrt(5)

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9x^2+9y^2+42x+84y+65=0

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

(a, b) = (- \frac{7}{3}, - \frac{14}{3}), r = 25

Solution steps

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

Rewrite

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

in the form of the standard circle equation

(x - (- \frac{7}{3}))^{2} + (y - (- \frac{14}{3}))^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{7}{3}, - \frac{14}{3}), r = 25

4 x^{2} + 4 y^{2} - 16 x - 24 y + 51 = 0

2 x^{2} + 2 y^{2} - 2 x + 6 y = 45

9 x^{2} + 9 y^{2} - 6 x + 24 y = 19

2 x^{2} + 2 y^{2} + 12 x - 2 y - 3 = 0

x^{2} + y^{2} + 8 x - 9 y = 6

What is 9x^2+9y^2+42x+84y+65=0 ?
The solution to 9x^2+9y^2+42x+84y+65=0 is Circle with (a,b)=(-7/3 ,-14/3),r=2sqrt(5)