What is the area 1/2 (6x)(4x-3) ?

The area 1/2 (6x)(4x-3) is Unbounded

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area 1/2 (6x)(4x-3)

area

\frac{1}{2} (6 x) (4 x - 3)

Unbounded

Solution steps

y = \frac{1}{2} \cdot 6 x (4 x - 3)

Rewrite

y = \frac{1}{2} \cdot 6 x (4 x - 3)

in the standard form

4 \cdot \frac{1}{48} (y - (- \frac{27}{16})) = (x - \frac{3}{8})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{8}, - \frac{27}{16}), p = \frac{1}{48}

Parabola's area is always unbounded

Unbounded

x^{2} + 3 x - 5

- 0.1 x^{2} + 7

- 0.75 x^{2} + 3 x

f (x) = x^{2} - 3 x - 4

y^{2} + 4 y