What is the area (6-x^2)+(x+4) ?

The area (6-x^2)+(x+4) is Unbounded

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area (6-x^2)+(x+4)

area

(6 - x^{2}) + (x + 4)

Unbounded

Solution steps

y = (6 - x^{2}) + x + 4

Rewrite

y = (6 - x^{2}) + x + 4

in the standard form

4 (- \frac{1}{4}) (y - \frac{41}{4}) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{41}{4}), p = - \frac{1}{4}

Parabola's area is always unbounded

Unbounded

y = x^{2} + 1 (- 2, 0)

x + 6 - x^{2}

x^{2} = 2 y + 4

f (x) = x^{2} + 1 (- 1, 2)

y = (1 + x) (4 - x)