What is the area f(x)=2x^2+3[-3,-1] ?

The area f(x)=2x^2+3[-3,-1] is Unbounded

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area f(x)=2x^2+3[-3,-1]

area

f (x) = 2 x^{2} + 3 [- 3, - 1]

Unbounded

Solution steps

y = 2 x^{2} + 3 [- 3, - 1]

Rewrite

y = 2 x^{2} + 3 [- 3, - 1]

in the standard form:

4 \cdot \frac{1}{8} (y - (- \frac{- \frac{3 [ - 3 , - 1 ]}{2}}{\frac{1}{2}})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{- \frac{3 [ - 3 , - 1 ]}{2}}{\frac{1}{2}}), p = \frac{1}{8}

Parabola's area is always unbounded

Unbounded

x^{2} - 12.4 x + 20

7 x^{2} - 2 x - 20 - (8 x^{2} - 15 x + 20)

\frac{p ^{2}}{16}

x = y^{2} + 1

0.9 x^{2} + 6.4 x + 7.7