What is the area f(x)=-x^2+3x+2 ?

The area f(x)=-x^2+3x+2 is Unbounded

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area f(x)=-x^2+3x+2

area

f (x) = - x^{2} + 3 x + 2

Unbounded

Solution steps

y = - x^{2} + 3 x + 2

Rewrite

y = - x^{2} + 3 x + 2

in the standard form

4 (- \frac{1}{4}) (y - \frac{17}{4}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{17}{4}), p = - \frac{1}{4}

Parabola's area is always unbounded

Unbounded

\frac{( y - 3 ) ^{2}}{5}

(- x + 2) - (x^{2} - 1)

x^{2} + 9 [- 1, 3]

616 c m^{2}

x + y^{2} = 20