What is x^2+y^2-9x+5y-10=0 ?

The solution to x^2+y^2-9x+5y-10=0 is Circle with (a,b)=(9/2 ,-5/2),r=sqrt(73/2)

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x^2+y^2-9x+5y-10=0

x^{2} + y^{2} - 9 x + 5 y - 10 = 0

(a, b) = (\frac{9}{2}, - \frac{5}{2}), r = \frac{73}{2}

Solution steps

x^{2} + y^{2} - 9 x + 5 y - 10 = 0

Rewrite

x^{2} + y^{2} - 9 x + 5 y - 10 = 0

in the form of the standard circle equation

(x - \frac{9}{2})^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{73}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{9}{2}, - \frac{5}{2}), r = \frac{73}{2}

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

(x - 3)^{2} + (y + 2)^{2} = 25

(x - 3)^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 8 x - 6 y = 0

(x - 1)^{2} + (y + 3)^{2} = 4

What is x^2+y^2-9x+5y-10=0 ?
The solution to x^2+y^2-9x+5y-10=0 is Circle with (a,b)=(9/2 ,-5/2),r=sqrt(73/2)