What is x^2+y^2+6y+2=0 ?

The solution to x^2+y^2+6y+2=0 is Circle with (a,b)=(0,-3),r=sqrt(7)

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x^2+y^2+6y+2=0

x^{2} + y^{2} + 6 y + 2 = 0

(a, b) = (0, - 3), r = 7

Solution steps

x^{2} + y^{2} + 6 y + 2 = 0

Rewrite

x^{2} + y^{2} + 6 y + 2 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 3))^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (0, - 3), r = 7

x^{2} + y^{2} + 4 x + 2 y - 20 = 0

3 x^{2} + 3 y^{2} + 4 y - 7 = 0

4 x^{2} + 4 y^{2} - 4 x + 12 y - 6 = 0

x^{2} + y^{2} + 4 x - 2 y - 11 = 0

(x^{2} - 14 x + 49) + (y^{2} + 8 y + 16) - 25 = 0

What is x^2+y^2+6y+2=0 ?
The solution to x^2+y^2+6y+2=0 is Circle with (a,b)=(0,-3),r=sqrt(7)