What is (y-1)^2+(x+5)^2=1 ?

The solution to (y-1)^2+(x+5)^2=1 is Circle with (a,b)=(-5,1),r=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y-1)^2+(x+5)^2=1

(y - 1)^{2} + (x + 5)^{2} = 1

(a, b) = (- 5, 1), r = 1

Solution steps

(y - 1)^{2} + (x + 5)^{2} = 1

Rewrite

(y - 1)^{2} + (x + 5)^{2} = 1

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 5, 1), r = 1

16 x^{2} + 80 x + 16 y^{2} - 112 y + 247 = 0

(x + 3)^{2} + (y - 4)^{2} = 25

x^{2} + y^{2} + 6 x - 2 y - 3 = 0

(x + 2)^{2} + (y - 3)^{2} = 16

x^{2} + y^{2} - x + 2 y + 1 = 0

What is (y-1)^2+(x+5)^2=1 ?
The solution to (y-1)^2+(x+5)^2=1 is Circle with (a,b)=(-5,1),r=1