What is 3y+6x-3x^2-3y^2=-1 ?

The solution to 3y+6x-3x^2-3y^2=-1 is Circle with (a,b)=(1, 1/2),r=(sqrt(19))/(2sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3y+6x-3x^2-3y^2=-1

3 y + 6 x - 3 x^{2} - 3 y^{2} = - 1

(a, b) = (1, \frac{1}{2}), r = \frac{19}{2 3}

Solution steps

3 y + 6 x - 3 x^{2} - 3 y^{2} = - 1

Rewrite

3 y + 6 x - 3 x^{2} - 3 y^{2} = - 1

in the form of the standard circle equation

(x - 1)^{2} + (y - \frac{1}{2})^{2} = (\frac{19}{2 3})^{2}

Therefore the circle properties are:

(a, b) = (1, \frac{1}{2}), r = \frac{19}{2 3}

x^{2} + y^{2} + 6 x - 4 y - 3 = 0

x^{2} + y^{2} - 12 x + 20 y + 15 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

x^{2} + y^{2} + 4 x - 6 y - 10 = 0

x^{2} + (y + 1)^{2} = 4

What is 3y+6x-3x^2-3y^2=-1 ?
The solution to 3y+6x-3x^2-3y^2=-1 is Circle with (a,b)=(1, 1/2),r=(sqrt(19))/(2sqrt(3))