en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2+z^2=4

Solution

y^{2} + z^{2} = 4

Solution

(a, b) = (0, 0), r = 2

Solution steps

y^{2} + z^{2} = 4

Rewrite

y^{2} + z^{2} = 4

in the form of the standard circle equation

(y - 0)^{2} + (z - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

Popular Examples

y^{2} + x^{2} = 4

x^{2} + y^{2} - 6 y + 5 = 0

x^2+(y+3/2)^2=4

x^{2} + (y + \frac{3}{2})^{2} = 4

x^2+y^2-4x-2y-20=0

x^{2} + y^{2} - 4 x - 2 y - 20 = 0

x^2-8x+y^2+6y=-9

x^{2} - 8 x + y^{2} + 6 y = - 9

Frequently Asked Questions (FAQ)

What is y^2+z^2=4 ?
The solution to y^2+z^2=4 is Circle with (a,b)=(0,0),r=2