What is 3(x-5)^2+3(y+9)^2=48 ?

The solution to 3(x-5)^2+3(y+9)^2=48 is Circle with (a,b)=(5,-9),r=4

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3(x-5)^2+3(y+9)^2=48

3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

(a, b) = (5, - 9), r = 4

Solution steps

3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

Rewrite

3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 9))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, - 9), r = 4

x^{2} + y^{2} \geq 1

(x + 2)^{2} + (y - 1)^{2} = 9

x^{2} + y^{2} = 225

x^{2} + y^{2} + 2 x - 4 y - 15 = 0

x^{2} + y^{2} + 6 x - 2 y + 9 = 0

What is 3(x-5)^2+3(y+9)^2=48 ?
The solution to 3(x-5)^2+3(y+9)^2=48 is Circle with (a,b)=(5,-9),r=4