What is 16x^2+96x+16y^2-40y=315 ?

The solution to 16x^2+96x+16y^2-40y=315 is Circle with (a,b)=(-3, 5/4),r= 11/2

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16x^2+96x+16y^2-40y=315

16 x^{2} + 96 x + 16 y^{2} - 40 y = 315

(a, b) = (- 3, \frac{5}{4}), r = \frac{11}{2}

Solution steps

16 x^{2} + 96 x + 16 y^{2} - 40 y = 315

Rewrite

16 x^{2} + 96 x + 16 y^{2} - 40 y = 315

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{5}{4})^{2} = (\frac{11}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{5}{4}), r = \frac{11}{2}

x^{2} - 4 x + y^{2} + 8 y = - 4

x^{2} + y^{2} + 4 y - 1 = 0

x^{2} + y^{2} + 4 x - 8 y + 9 = 0

x^{2} + y^{2} < 25

x^{2} + y^{2} - 6 x + 2 y - 6 = 0

What is 16x^2+96x+16y^2-40y=315 ?
The solution to 16x^2+96x+16y^2-40y=315 is Circle with (a,b)=(-3, 5/4),r= 11/2