What is x^2-2x+y^2+4y=4 ?

The solution to x^2-2x+y^2+4y=4 is Circle with (a,b)=(1,-2),r=3

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x^2-2x+y^2+4y=4

x^{2} - 2 x + y^{2} + 4 y = 4

(a, b) = (1, - 2), r = 3

Solution steps

x^{2} - 2 x + y^{2} + 4 y = 4

Rewrite

x^{2} - 2 x + y^{2} + 4 y = 4

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 3

x = 2 y^{2}

f (x) = - x^{2}

- \frac{1}{20} x^{2}

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

x^{2} = - 24 y

What is x^2-2x+y^2+4y=4 ?
The solution to x^2-2x+y^2+4y=4 is Circle with (a,b)=(1,-2),r=3