What is x^2+z^2+4x-4z=-4 ?

The solution to x^2+z^2+4x-4z=-4 is Circle with (a,b)=(-2,2),r=2

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x^2+z^2+4x-4z=-4

x^{2} + z^{2} + 4 x - 4 z = - 4

(a, b) = (- 2, 2), r = 2

Solution steps

x^{2} + z^{2} + 4 x - 4 z = - 4

Rewrite

x^{2} + z^{2} + 4 x - 4 z = - 4

in the form of the standard circle equation

(x - (- 2))^{2} + (z - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, 2), r = 2

x^{2} + y^{2} + 6 x + 4 y + 4 = 0

x^{2} - 4 x + y^{2} + 2 y + 1 = 0

(x + 2)^{2} + (y - 2)^{2} = 4

x^{2} + y^{2} + 4 x - 6 y + 4 = 0

x^{2} + y^{2} - 12 = 0

What is x^2+z^2+4x-4z=-4 ?
The solution to x^2+z^2+4x-4z=-4 is Circle with (a,b)=(-2,2),r=2