What is x^2+y^2+8y=2x+20 ?

The solution to x^2+y^2+8y=2x+20 is Circle with (a,b)=(1,-4),r=sqrt(37)

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x^2+y^2+8y=2x+20

x^{2} + y^{2} + 8 y = 2 x + 20

(a, b) = (1, - 4), r = 37

Solution steps

x^{2} + y^{2} + 8 y = 2 x + 20

Rewrite

x^{2} + y^{2} + 8 y = 2 x + 20

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 4))^{2} = (37)^{2}

Therefore the circle properties are:

(a, b) = (1, - 4), r = 37

(x - 1)^{2} + (y - 1)^{2} = 1

x^{2} + y^{2} + 7 x - 8 y = 3

x^{2} + y^{2} + 6 x - 8 y = 0

y^{2} = 49 - x^{2}

x^{2} + y^{2} + 16 x - 8 y + 76 = 0

What is x^2+y^2+8y=2x+20 ?
The solution to x^2+y^2+8y=2x+20 is Circle with (a,b)=(1,-4),r=sqrt(37)