What is (x+1)^2+(y-1)^2=1.25 ?

The solution to (x+1)^2+(y-1)^2=1.25 is Circle with (a,b)=(-1,1),r=1.11803…

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(x+1)^2+(y-1)^2=1.25

(x + 1)^{2} + (y - 1)^{2} = 1.25

(a, b) = (- 1, 1), r = 1.11803 \dots

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 1.25

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 1.25

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = 1.11803 \dots^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 1.11803 \dots

(x - 3)^{2} + (y - 1)^{2} = 36

x^{2} + y^{2} + 2 x = 8

(x + 5)^{2} + (y - 6)^{2} = 4

(x - 3)^{2} + (y - 4)^{2} = 25

y^{2} = 25 - x^{2}

What is (x+1)^2+(y-1)^2=1.25 ?
The solution to (x+1)^2+(y-1)^2=1.25 is Circle with (a,b)=(-1,1),r=1.11803…