What is (x-4)^2+(y-7)^2=49 ?

The solution to (x-4)^2+(y-7)^2=49 is Circle with (a,b)=(4,7),r=7

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(x-4)^2+(y-7)^2=49

(x - 4)^{2} + (y - 7)^{2} = 49

(a, b) = (4, 7), r = 7

Solution steps

(x - 4)^{2} + (y - 7)^{2} = 49

Rewrite

(x - 4)^{2} + (y - 7)^{2} = 49

in the form of the standard circle equation

(x - 4)^{2} + (y - 7)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (4, 7), r = 7

9 x^{2} + 9 y^{2} - 42 x + 84 y + 65 = 0

x^{2} + y^{2} + 8 x - 2 y + 8 = 0

2 x^{2} + 8 x + 2 y^{2} - 16 y - 5 = 0

x^{2} + y^{2} + 8 x - 12 y + 27 = 0

4 x^{2} + 4 y^{2} - 4 x + 2 y + 1 = 0

What is (x-4)^2+(y-7)^2=49 ?
The solution to (x-4)^2+(y-7)^2=49 is Circle with (a,b)=(4,7),r=7