What is (x-3/2)^2+(y-3)^2= 29/4 ?

The solution to (x-3/2)^2+(y-3)^2= 29/4 is Circle with (a,b)=(3/2 ,3),r=sqrt(29/4)

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(x-3/2)^2+(y-3)^2= 29/4

(x - \frac{3}{2})^{2} + (y - 3)^{2} = \frac{29}{4}

(a, b) = (\frac{3}{2}, 3), r = \frac{29}{4}

Solution steps

(x - \frac{3}{2})^{2} + (y - 3)^{2} = \frac{29}{4}

Rewrite

(x - \frac{3}{2})^{2} + (y - 3)^{2} = \frac{29}{4}

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 3)^{2} = (\frac{29}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 3), r = \frac{29}{4}

(x + 3)^{2} + (y - 5)^{2} = 36

x^{2} + y^{2} - 4 y - 12 = 0

x^{2} + y^{2} - 4 x - 6 y + 8 = 0

x^{2} + y^{2} - 6 x + 5 = 1

x^{2} + y^{2} + 6 x - 7 = 0

What is (x-3/2)^2+(y-3)^2= 29/4 ?
The solution to (x-3/2)^2+(y-3)^2= 29/4 is Circle with (a,b)=(3/2 ,3),r=sqrt(29/4)