What is (x+3)^2+(y-4)^2=49 ?

The solution to (x+3)^2+(y-4)^2=49 is Circle with (a,b)=(-3,4),r=7

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(x+3)^2+(y-4)^2=49

(x + 3)^{2} + (y - 4)^{2} = 49

(a, b) = (- 3, 4), r = 7

Solution steps

(x + 3)^{2} + (y - 4)^{2} = 49

Rewrite

(x + 3)^{2} + (y - 4)^{2} = 49

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 7

x^{2} + y^{2} - 6 x + 2 y + 1 = 0

x^{2} + y^{2} - 4 x + 10 y + 23 = 0

4 x^{2} + 4 y^{2} + 8 x - 16 y - 29 = 0

x^{2} + y^{2} - 6 x - 2 y - 6 = 0

(x - 2)^{2} + (y + 3)^{2} = 36

What is (x+3)^2+(y-4)^2=49 ?
The solution to (x+3)^2+(y-4)^2=49 is Circle with (a,b)=(-3,4),r=7