What is x^2-8x+y^2-10y=40 ?

The solution to x^2-8x+y^2-10y=40 is Circle with (a,b)=(4,5),r=9

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x^2-8x+y^2-10y=40

x^{2} - 8 x + y^{2} - 10 y = 40

(a, b) = (4, 5), r = 9

Solution steps

x^{2} - 8 x + y^{2} - 10 y = 40

Rewrite

x^{2} - 8 x + y^{2} - 10 y = 40

in the form of the standard circle equation

(x - 4)^{2} + (y - 5)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (4, 5), r = 9

x^{2} + y^{2} - 6 x + 2 y + 4 = 0

9 = x^{2} + y^{2}

x^{2} + y^{2} + 10 x + 12 y + 12 = 0

(x + 3)^{2} + (y - 0)^{2} = 16

x^{2} + y^{2} + 14 x - 16 y + 86 = 0

What is x^2-8x+y^2-10y=40 ?
The solution to x^2-8x+y^2-10y=40 is Circle with (a,b)=(4,5),r=9