What is x^2+y^2-4x+4= 9/16 ?

The solution to x^2+y^2-4x+4= 9/16 is Circle with (a,b)=(2,0),r= 3/4

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x^2+y^2-4x+4= 9/16

x^{2} + y^{2} - 4 x + 4 = \frac{9}{16}

(a, b) = (2, 0), r = \frac{3}{4}

Solution steps

x^{2} + y^{2} - 4 x + 4 = \frac{9}{16}

Rewrite

x^{2} + y^{2} - 4 x + 4 = \frac{9}{16}

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = (\frac{3}{4})^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = \frac{3}{4}

(x + 2)^{2} + (y + 5)^{2} = 144

4 x^{2} + 4 y^{2} - 4 x - 8 y - 11 = 0

x^{2} + y^{2} + x + 6 y + 9 = 0

x^{2} + y^{2} + 4 x + 2 y - 4 = 0

x^{2} + y^{2} - x - 8 y + 16 = 0

What is x^2+y^2-4x+4= 9/16 ?
The solution to x^2+y^2-4x+4= 9/16 is Circle with (a,b)=(2,0),r= 3/4