What is (x+4)^2+(y-6)^2=18 ?

The solution to (x+4)^2+(y-6)^2=18 is Circle with (a,b)=(-4,6),r=sqrt(18)

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(x+4)^2+(y-6)^2=18

(x + 4)^{2} + (y - 6)^{2} = 18

(a, b) = (- 4, 6), r = 18

Solution steps

(x + 4)^{2} + (y - 6)^{2} = 18

Rewrite

(x + 4)^{2} + (y - 6)^{2} = 18

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 6)^{2} = (18)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 6), r = 18

x^{2} + y^{2} + x - 6 y + 9 = 0

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

16 x^{2} + 16 y^{2} - 8 y - 15 = 0

y^{2} + 2 x + x^{2} = 24 y - 120

(x + 1)^{2} + (y + 2)^{2} = 9

What is (x+4)^2+(y-6)^2=18 ?
The solution to (x+4)^2+(y-6)^2=18 is Circle with (a,b)=(-4,6),r=sqrt(18)